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x^2-30x-1650=0
a = 1; b = -30; c = -1650;
Δ = b2-4ac
Δ = -302-4·1·(-1650)
Δ = 7500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7500}=\sqrt{2500*3}=\sqrt{2500}*\sqrt{3}=50\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-50\sqrt{3}}{2*1}=\frac{30-50\sqrt{3}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+50\sqrt{3}}{2*1}=\frac{30+50\sqrt{3}}{2} $
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